Clarifications officielles de Wizards of the Coast. La traduction FR ci-dessous est générée automatiquement (IA) — l'original anglais reste la source de vérité.
08 novembre 2024 · source : wotc
The kicker ability doesn't let you pay a kicker cost more than once.
08 novembre 2024 · source : wotc
If you copy a kicked spell on the stack, the copy is also kicked. If the copied spell is a permanent spell, the token the copy of that spell becomes when it enters is also kicked.
08 novembre 2024 · source : wotc
If a card or token enters as a copy of a permanent, the new permanent isn't kicked, even if the original was.
08 novembre 2024 · source : wotc
If you put a permanent with a kicker ability onto the battlefield without casting it, you can't kick it.
08 novembre 2024 · source : wotc
If a spell's kicker cost was paid, the spell is "kicked."
08 novembre 2024 · source : wotc
To determine a spell's total cost, start with the mana cost (or an alternative cost if another card's effect allows you to pay one instead), add any cost increases (such as kicker), then apply any cost reductions. The spell's mana value remains unchanged, no matter what the total cost to cast it was.
01 mars 2010 · source : wotc
As long as any of its targets are legal at the time Comet Storm resolves, Comet Storm will deal X damage to each of those legal targets.
01 mars 2010 · source : wotc
The number of targets you choose for Comet Storm is one more than the number of times it's kicked. First you declare how many times you're going to kick the spell (at the same time you declare the value of X), then you choose the targets accordingly, then you pay the costs. No player can respond between the time you declare how many times you'll kick the spell and the time you choose the targets.
01 mars 2010 · source : wotc
Each target you choose must be different.
01 mars 2010 · source : wotc
For example, if you want Comet Storm to deal 4 damage to each of three different targets, that means X is 4 and you're kicking the spell twice. You'll pay a mana cost of {4}{R}{R}, plus a kicker cost of {1}, plus another kicker cost of {1}, for a total of {6}{R}{R}.
